16x^2+400x=0

Solution for 16x^2+400x=0 equation:

16x^2+400x=0

a = 16; b = 400; c = 0;
Δ = b2-4ac
Δ = 4002-4·16·0
Δ = 160000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{160000}=400$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(400)-400}{2*16}=\frac{-800}{32}
=-25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(400)+400}{2*16}=\frac{0}{32}
=0
$